One of my wing-mates recently attempted the record distance from Sol, so we got talking about fuel efficiency and max distance. I saw the thread that listed Cmdr. Mcgrew's 65,804.4 LY accomplishment. I began to wonder if my little DBX could ever go that far. So, I started to attempt to calculate the math. But I ran into problems. Either my math isn't working, or there's something funny going on. Now, I'm an English Language Arts teacher - not a mathematician, so I'm asking for your help in double checking my math and reasoning.

Let's start with the speed of light, our constant. Google tells me that's 299,792,458 meters/second. (Which is odd. I always thought it was meters/second^2).

So, I know from my wing-mate that max speed is 2001c, which equals 5.99885E+11 meters/second.

Fine.

I really need the speed in meters/hour, though, because my fuel burn rate is listed in tons / hour.

So, 5.99885E+11 meters/second * 60minutes/hour *60second/minute = 2.15958E+15 meters/hour.

So far, so good (I assume).

I need to know how many light years I can travel per hour to know the maximum number of light years I can get away from the star.

So, Google tells me 1 light year = 9.461E+15 meters. So far, so good.

Now, (1LY /9.461E+15 meters)/(2.15958E+15 meters/hour) = .228262 LY/hr

Okay. So, my wing-mate's ship has 800 tons of fuel. At 1.54 tons/hour (not what he's getting, it's actually what I'm getting - but it serves to make the point because his fuel efficiency isn't much different), he can burn for roughly 519 hours.

Now, 519 hours (burn time) * .228262 LY/hr = 118.4679 LY max distance.

This doesn't account for the possibility of a return trip. I'm just trying to figure out the math.

If the main star in Oevasy SG-Y d0 is 65,647.34, then: 65,647.34 + 118.4679 = 65,765.81 maximum distance from the star.

Correct?

So, if I want to get to 65,804.4 LY from Oevasy SG-Y d0, I need to travel an additional 157.06 LY from the star.

That means, traveling at .228262 LY/hr, I need 688.0696 hours of burn time. (157.06 LY / .228262 LY/hr = 688.0696 hours).

Now, knowing I burn at 1.54 tons / hour, I need 105.9627 tons of fuel (1.54 tons / hour * 688.0696 hours = 1,059.627 tons).

Phew.

Does this math seem correct?

Thanks in advance.

~Tim

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