Does anyone know about the size/volume of the bubble/pill of inhibated systems

[wolverine2710]

There are roughly 20K systems or so which are inhabited (PRE horizons). Does any one know the volume of the bubble. Also quantities like length, diameter etc would be great to know. I need these statistic for a post I'm creating. I guess it has been discussed some time in the past but can't find it. Any help is very much appreacited.

 

[RoadRunner]

Not sure of the exact details, but I'm sure Frontier have said several times that the inhabited region of the galaxy is about 200 square light years with Sol at the centre.

 

[ratchet5000]

Not sure of the exact details, but I'm sure Frontier have said several times that the inhabited region of the galaxy is about 200 square light years with Sol at the centre.

Square is area not volume. Cubic light years maybe?

 

[AH_ImADot]

Maybe they mean a sphere with a radius of 200ly.

 

[RoadRunner]

Square is area not volume. Cubic light years maybe?

Yeah, I was meaning cubic light years. I think it's definitely cubic rather than a sphere are space is divided into cubic sectors.

 

[goemon]

the bubble is no ball, though. also, the question is, where you let it end (e.g.: do you take new colonies like sothis into account, or not?). if you look to the industrial systes furthest away from sol on x/z/y, you'll get like:

175 ly radius on z-axis around sol
280 ly radius on x axis
250 ly radius on y axis

the two centers of this geometrical body called bubble are sol and achenar.

 

[Slugsie]

200 cubic light years is a cube less than 6Ly a side (6x6x6 = 216), which if centered on Sol gets you to roughly Barnards Star. Even a cube of 2000 cubic Ly is only just over 12.5Ly a side. A sphere of radius 200Ly is much more likely. That's 33,510,321 Cubic Light Years if anyone is interested.

*edit*
Of course it's not a strict regular shape anyways. It's more of a blob in reality.

 

[Ralph Vargr]

the bubble is no ball, though. also, the question is, where you let it end (e.g.: do you take new colonies like sothis into account, or not?). if you look to the industrial systes furthest away from sol on x/z/y, you'll get like:

175 ly radius on z-axis around sol
280 ly radius on x axis
250 ly radius on y axis

the two centers of this geometrical body called bubble are sol and achenar.

Ellipsoid. Try asking Finn at EDD for more data.

 

[Loskene]

You used to be able to zoom the galmap out and see the entire bubble's outer dimensions with map view on, but they changed that at some point, presumably as an "optimization" effort to get the thing to work reasonably well. I do hope they find a way to increase the draw distance again, it was nice being able to get an overview of all of inhabited space and your location within it, from Alliance to Empire.

 

[wolverine2710]

My math skills are crappy. Can someone gives an estimate (based upon the info here) what the volume of the geometric shape is.

I did some digging but can't find it back - not even in EDcodex. Right after the launch in December 2014 Michael Brookes supplied us with a list of approc 20K systems (with coordinates). Some one from the crowd sourcing thread create a small program displaying in 3D all the systems. If someone knows what I'm talking about please be so kind to post it here.

 

[Winterwalker]

My math skills are crappy. Can someone gives an estimate (based upon the info here) what the volume of the geometric shape is.

Estimating on;
175 ly radius on z-axis around sol
280 ly radius on x axis
250 ly radius on y axis

... by approximating to a sphere

AVERAGE radius, r
= (175 + 280 + 250) / 3
= 235 Ly

Volume of sphere, V = ( 4/3 . pi . r^3 )
= 5.44×10^7
= 54,400,000 cubic Ly's (approx)

Spoiler

Fun fact; 1 cubic light year
= 8.46732407987 × 10E+50 litres

Volume of "bubble" (on the above calculated estimate) =
46,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 litres (approx)

source

 

[wolverine2710]

Estimating on;
175 ly radius on z-axis around sol
280 ly radius on x axis
250 ly radius on y axis

... by approximating to a sphere

AVERAGE radius, r
= (175 + 280 + 250) / 3
= 235 Ly

Volume of sphere, V = ( 4/3 . pi . r^3 )
= 5.44×10^7
= 54,400,000 cubic Ly's (approx)

Spoiler

Fun fact; 1 cubic light year
= 8.46732407987 × 10+50 litres

Volume of "bubble" (on the above, calculated estimate) =
46,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 litres (approx)

Perfecto. This estimate is very useful for me. Will be used in a upcoming post in the "Open Letter to Frontier Developments" thread to put things a bit in perspective.

 

[Winterwalker]

o7 Commander

 

[tricky]

I know you have an answer, but since I looked it up here is an alternative that gives a slightly bigger cubic volume of space.

--
Could have used the average of the 3 spheroids.

Volume of a spheroid = (4/3 . pi) . a² . c

S[SUB]1[/SUB] -> a = 280, c = 250
S[SUB]2[/SUB] -> a = 280, c = 175
S[SUB]3[/SUB] -> a = 250, c = 175

S[SUB]1[/SUB] = (4/3 . pi) . 280² . 250 ~= 82,100,000 cubic LY
S[SUB]2[/SUB] = (4/3 . pi) . 280² . 175 ~= 57,470,000 cubic LY
S[SUB]3[/SUB] = (4/3 . pi) . 250² . 175 ~= 45,815,000 cubic LY

Average volume = (S[SUB]1[/SUB] + S[SUB]2[/SUB] + S[SUB]3[/SUB]) / 3

= (8.21x10⁷ + 5.747x10⁷ + 4.5815x10⁷) / 3
= 1.85385x10⁸ / 3
---------------------------
= 61,795,000 cubic LY

 

[wolverine2710]

I know you have an answer, but since I looked it up here is an alternative that gives a slightly bigger cubic volume of space.

--
Could have used the average of the 3 spheroids.

Volume of a spheroid = (4/3 . pi) . a² . c

S[SUB]1[/SUB] -> a = 280, c = 250
S[SUB]2[/SUB] -> a = 280, c = 175
S[SUB]3[/SUB] -> a = 250, c = 175

S[SUB]1[/SUB] = (4/3 . pi) . 280² . 250 ~= 82,100,000 cubic LY
S[SUB]2[/SUB] = (4/3 . pi) . 280² . 175 ~= 57,470,000 cubic LY
S[SUB]3[/SUB] = (4/3 . pi) . 250² . 175 ~= 45,815,000 cubic LY

Average volume = (S[SUB]1[/SUB] + S[SUB]2[/SUB] + S[SUB]3[/SUB]) / 3

= (8.21x10⁷ + 5.747x10⁷ + 4.5815x10⁷) / 3
= 1.85385x10⁸ / 3
---------------------------
= 61,795,000 cubic LY

Cool, thanks a lot
Rep +1 for you, winterwalker and goemon.
As it are both estimates I think I'm going to take the avg off both estimated cubic LY.

Thanks for all the help commanders. Very much appreciated!!!

 

[Winterwalker]

Cool, thanks a lot
Rep +1 for you, winterwalker and goemon.
As it are both estimates I think I'm going to take the avg off both estimated cubic LY.

Thanks for all the help commanders. Very much appreciated!!!

A *round* 60 million cubic light years, should do just fine I'd say.

That skews the average a tiny bit toward the second, more sophisticated figure ..
.. but is one smexy number!

 

[CMDR Byr Goefin]

What is the population?

Looks to be around 6 or 7 Trillion, but I am guessing I am on the low side.

 

[Winterwalker]

What is the population?

Looks to be around 6 or 7 Trillion, but I am guessing I am on the low side.

Nice. You could also ask how many players, and how much space we have "each"

edit ---
no idea on the population but was wondering if there's a way to break the area up into chunks, like it is in the powerplay map.

 

[CMDR Byr Goefin]

Nice. You could also ask how many players, and how much space we have "each"

No, I was interested in the population of Flatlanders, not the Spacers.

 

[Winterwalker]

No, I was interested in the population of Flatlanders, not the Spacers.

Is there any way to work it out from powerplay, CC's?