The Hunt For Theta Seven - You Could Win 750,000,000 Cr!

CMDRs,

Apologies for the delayed explanation of how I deciphered this. I had to high-tail it to Panjabell to look for anything unusual. There is nothing apparent there, but I haven't searched exhaustively yet. Please feel free to join in the hunt at Panjabell.

Like many, I tried a number of techniques to no avail until I stumbled upon the right one. The key was indeed the fake traffic logs. Using the incrementing Type-7 numbers to determine order, the other ship types spelled out a 7x7 matrix, namely:


0​
0​
1​
2​
1​
1​
2​
0​
2​
1​
0​
1​
3​
0​
2​
0​
0​
1​
2​
0​
2​
3​
0​
0​
2​
0​
0​
2​
0​
2​
3​
0​
1​
1​
0​
2​
2​
0​
1​
1​
0​
1​
0​
1​
2​
1​
1​
2​
0​

Assuming this to be the key, I arranged the numerical ciphertext provided in the Galnet article into a matrix 7 columns by 24 rows. I then multiplied it by the inverse of the key above. The result yielded a reasonable number of unique values, 27 (with 30 being an outlier). To me, this appeared to be the alphabet (single case) plus a space. I started with 1=A, 2=B, etc. I set the remaining values after Z to space. This deciphered to the message I posted, to my surprise.

Good luck recreating my results. I used Excel for all of this. Good luck to us all in tracking down Theta 7 from here, and I'll see you in the black!

o7,
CMDR Therion Cygni
How interesting. I did that last night and got nothing useful.

Do you mind showing me the two matrices.
 
His method worked when I tried it, FYI.
Do you have a screenshot of the inverse matrix?

At this point, it's not that I don't trust the response, it's exactly what should have worked... but it didn't in my previous post. So just wondering where I went wrong.

EDIT: Just to illustrate a bit better, these are the bits.

Inverse matrix is calculated as "MINVERSE(K1:Q7)"
Result is calculated as "MMULT(A1:G24;R1:X7)"

... in OO Calc.


1636932637907.png
 
Last edited:
Do you have a screenshot of the inverse matrix?

At this point, it's not that I don't trust the response, it's exactly what should have worked... but it didn't in my previous post. So just wondering where I went wrong.
Here is my inverse of the key:
-0.40816​
0.020408​
0.163265​
0.306122​
0.020408​
-0.12245​
0.163265​
0.163265​
0.091837​
-0.26531​
-0.12245​
0.091837​
0.44898​
-0.26531​
-0.05102​
-0.12245​
0.020408​
0.163265​
0.377551​
-0.26531​
0.020408​
0.163265​
-0.40816​
-0.26531​
-0.12245​
-0.40816​
0.44898​
0.734694​
-0.12245​
-0.19388​
0.44898​
-0.40816​
-0.19388​
0.163265​
0.44898​
-0.05102​
0.377551​
0.020408​
0.163265​
-0.12245​
-0.26531​
0.020408​
0.44898​
0.377551​
0.020408​
0.163265​
0.377551​
-0.26531​
-0.97959​

Here is the result of multiplying the numerical ciphertext by the inverse key:
8​
1​
22​
5​
27​
1​
18​
18​
9​
22​
5​
4​
27​
1​
20​
27​
16​
1​
14​
10​
1​
2​
5​
12​
12​
27​
27​
23​
5​
1​
16​
15​
14​
19​
27​
18​
5​
13​
1​
9​
14​
27​
19​
5​
3​
21​
18​
5​
27​
27​
9​
27​
14​
15​
27​
12​
15​
14​
7​
5​
18​
27​
20​
18​
21​
19​
20​
27​
15​
21​
18​
27​
2​
5​
14​
5​
6​
1​
3​
20​
15​
18​
19​
27​
15​
18​
27​
20​
8​
5​
9​
18​
27​
14​
5​
20​
23​
15​
18​
11​
30​
27​
23​
5​
27​
23​
9​
12​
12​
27​
2​
5​
3​
15​
13​
5​
27​
9​
14​
22​
9​
19​
9​
2​
12​
5​
27​
21​
14​
20​
9​
12​
27​
20​
8​
5​
27​
20​
9​
13​
5​
27​
9​
19​
27​
18​
9​
7​
8​
20​
27​
20​
15​
27​
19​
20​
18​
9​
11​
5​
27​
1​
7​
1​
9​
14​
27​
27​

o7
 
Here is my inverse of the key:
-0.40816​
0.020408​
0.163265​
0.306122​
0.020408​
-0.12245​
0.163265​
0.163265​
0.091837​
-0.26531​
-0.12245​
0.091837​
0.44898​
-0.26531​
-0.05102​
-0.12245​
0.020408​
0.163265​
0.377551​
-0.26531​
0.020408​
0.163265​
-0.40816​
-0.26531​
-0.12245​
-0.40816​
0.44898​
0.734694​
-0.12245​
-0.19388​
0.44898​
-0.40816​
-0.19388​
0.163265​
0.44898​
-0.05102​
0.377551​
0.020408​
0.163265​
-0.12245​
-0.26531​
0.020408​
0.44898​
0.377551​
0.020408​
0.163265​
0.377551​
-0.26531​
-0.97959​

Here is the result of multiplying the numerical ciphertext by the inverse key:
8​
1​
22​
5​
27​
1​
18​
18​
9​
22​
5​
4​
27​
1​
20​
27​
16​
1​
14​
10​
1​
2​
5​
12​
12​
27​
27​
23​
5​
1​
16​
15​
14​
19​
27​
18​
5​
13​
1​
9​
14​
27​
19​
5​
3​
21​
18​
5​
27​
27​
9​
27​
14​
15​
27​
12​
15​
14​
7​
5​
18​
27​
20​
18​
21​
19​
20​
27​
15​
21​
18​
27​
2​
5​
14​
5​
6​
1​
3​
20​
15​
18​
19​
27​
15​
18​
27​
20​
8​
5​
9​
18​
27​
14​
5​
20​
23​
15​
18​
11​
30​
27​
23​
5​
27​
23​
9​
12​
12​
27​
2​
5​
3​
15​
13​
5​
27​
9​
14​
22​
9​
19​
9​
2​
12​
5​
27​
21​
14​
20​
9​
12​
27​
20​
8​
5​
27​
20​
9​
13​
5​
27​
9​
19​
27​
18​
9​
7​
8​
20​
27​
20​
15​
27​
19​
20​
18​
9​
11​
5​
27​
1​
7​
1​
9​
14​
27​
27​

o7
Aaaaah I see, I rotated the traffic report matrix. Goddamnit.

EDIT: I don't know what's happened with my middle row, but regardless, it looks good. Well done mate.
1636933155607.png
 
Last edited:
CMDRs,

Apologies for the delayed explanation of how I deciphered this. I had to high-tail it to Panjabell to look for anything unusual. There is nothing apparent there, but I haven't searched exhaustively yet. Please feel free to join in the hunt at Panjabell.

Like many, I tried a number of techniques to no avail until I stumbled upon the right one. The key was indeed the fake traffic logs. Using the incrementing Type-7 numbers to determine order, the other ship types spelled out a 7x7 matrix, namely:


0​
0​
1​
2​
1​
1​
2​
0​
2​
1​
0​
1​
3​
0​
2​
0​
0​
1​
2​
0​
2​
3​
0​
0​
2​
0​
0​
2​
0​
2​
3​
0​
1​
1​
0​
2​
2​
0​
1​
1​
0​
1​
0​
1​
2​
1​
1​
2​
0​

Assuming this to be the key, I arranged the numerical ciphertext provided in the Galnet article into a matrix 7 columns by 24 rows. I then multiplied it by the inverse of the key above. The result yielded a reasonable number of unique values, 27 (with 30 being an outlier). To me, this appeared to be the alphabet (single case) plus a space. I started with 1=A, 2=B, etc. I set the remaining values after Z to space. This deciphered to the message I posted, to my surprise.

Good luck recreating my results. I used Excel for all of this. Good luck to us all in tracking down Theta 7 from here, and I'll see you in the black!

o7,
CMDR Therion Cygni
Well great job ! I though about the inverse, but when I saw it gave me floatting numbers I though "nah, it won't give my anything usefull", and then I realised I flipped the multiplication wrong...
GG !
 
Run an internet search for matrix inversion. There are a number of educational sources, and even some handy tools to help with the calculations.
Ah, gotcha... a quick readup in my native language reminded me on how that worked....

Here's a bit of salt though: Matrices are more advanced algebra, I highly doubt that most people were teached those ever in their lifetime at one point or another :unsure:
 
Interesting timing of things in Panjabell.

July 22nd: Initiative to help Far God Cult prep new ships (Testament, Perdition, Sacrosanct)
July 31st: Theta 7 headed to Panjabell
August 6th: The launch of the Testament, Perdition, Sacrosanct

Is it possible Theta 7 is hiding among the Far God cultists on one of the ships?
 
CMDRs,

Apologies for the delayed explanation of how I deciphered this. I had to high-tail it to Panjabell to look for anything unusual. There is nothing apparent there, but I haven't searched exhaustively yet. Please feel free to join in the hunt at Panjabell.

Like many, I tried a number of techniques to no avail until I stumbled upon the right one. The key was indeed the fake traffic logs. Using the incrementing Type-7 numbers to determine order, the other ship types spelled out a 7x7 matrix, namely:


0​
0​
1​
2​
1​
1​
2​
0​
2​
1​
0​
1​
3​
0​
2​
0​
0​
1​
2​
0​
2​
3​
0​
0​
2​
0​
0​
2​
0​
2​
3​
0​
1​
1​
0​
2​
2​
0​
1​
1​
0​
1​
0​
1​
2​
1​
1​
2​
0​

Assuming this to be the key, I arranged the numerical ciphertext provided in the Galnet article into a matrix 7 columns by 24 rows. I then multiplied it by the inverse of the key above. The result yielded a reasonable number of unique values, 27 (with 30 being an outlier). To me, this appeared to be the alphabet (single case) plus a space. I started with 1=A, 2=B, etc. I set the remaining values after Z to space. This deciphered to the message I posted, to my surprise.

Good luck recreating my results. I used Excel for all of this. Good luck to us all in tracking down Theta 7 from here, and I'll see you in the black!

o7,
CMDR Therion Cygni

Thanks for the explanation I was scratching my head at first as I'm not really familiar with matrices then when I twigged what you were saying I was able to pull it all together

I put your solution in a google sheet so others can see how it is done.


The formula for multiplying the matrices is so simple!

=mmult(A2:G25,minverse(A28:G34))
 
Thanks for the explanation I was scratching my head at first as I'm not really familiar with matrices then when I twigged what you were saying I was able to pull it all together

I put your solution in a google sheet so others can see how it is done.


The formula for multiplying the matrices is so simple!

=mmult(A2:G25,minverse(A28:G34))
Yeah, matrix calculations from basic principles are complex. But thanks to computers, it's no harder than A * B, so you don't really need any of that knowledge.

The hard part (or at least, apparently hard part XD) was just arranging the numbers correctly.
 
CMDRs,

Apologies for the delayed explanation of how I deciphered this. I had to high-tail it to Panjabell to look for anything unusual. There is nothing apparent there, but I haven't searched exhaustively yet. Please feel free to join in the hunt at Panjabell.

Like many, I tried a number of techniques to no avail until I stumbled upon the right one. The key was indeed the fake traffic logs. Using the incrementing Type-7 numbers to determine order, the other ship types spelled out a 7x7 matrix, namely:


0​
0​
1​
2​
1​
1​
2​
0​
2​
1​
0​
1​
3​
0​
2​
0​
0​
1​
2​
0​
2​
3​
0​
0​
2​
0​
0​
2​
0​
2​
3​
0​
1​
1​
0​
2​
2​
0​
1​
1​
0​
1​
0​
1​
2​
1​
1​
2​
0​

Assuming this to be the key, I arranged the numerical ciphertext provided in the Galnet article into a matrix 7 columns by 24 rows. I then multiplied it by the inverse of the key above. The result yielded a reasonable number of unique values, 27 (with 30 being an outlier). To me, this appeared to be the alphabet (single case) plus a space. I started with 1=A, 2=B, etc. I set the remaining values after Z to space. This deciphered to the message I posted, to my surprise.

Good luck recreating my results. I used Excel for all of this. Good luck to us all in tracking down Theta 7 from here, and I'll see you in the black!

o7,
CMDR Therion Cygni
Good one commander! Congratulations! I hope this criminal gets caught before killing more innocents.
 
Back
Top Bottom