w = (u + v)/(1 + uv/c²)
where c² is the speed of light squared. At so-called Newtonian (i.e., slow) speeds, the term uv/c² is pretty close to 0, and the equation reduces down to the familiar w = u + v. However, if we are traveling at, say, 0.9c (nine-tenths the speed of light), and we shoot a bullet forward also at 0.9c, we discover via the above formula that the slug doesn't attain an overall speed of 1.8c (i.e., more than the speed of light), but rather a modest
(0.9c + 0.9c)/(1 + [0.9]²) = 0.994c
(roughly).
Does this mean the bullet just dribbles out of the gun like a gumdrop, Not at all — to you, the space traveller, everything looks normal. However, a stationary observer would note that you were suffering from the unique effects of the Fitzgerald contraction — which is to say, (1) time would slow down for you (although you wouldn't realize it), and (2) you and your spaceship would get compressed like an accordion along your axis of travel.