Ran across this a few nights ago. Usually don't pay close attention to the details but this one caught my eye because the gravity was listed as exactly 1.00G
Then I noticed the mass is 0.7954 earth masses.
How can that be? 1G would by definition mean 1 earth mass.
Nope, your definition would be incorrect. To be more precise:
where are you subject to 1g? Gravity also depends on your distance from the center of mass, so if you're looking at surface gravity - which is what Elite gives you - that would be the radius of the planet. However, Earth's mean radius 6,371 km, while your planet's is 5,686 km. So what would be on Earth's surface would be 685 km above Qieduia DX-K b12-0 A 1.
Now, Elite gives you the gravity at surface level on the system map. If you fly towards a landable planet, you'll notice that the g indicator will rise the closer you get. If you wish to calculate the surface gravity of the planet using the measurements Elite gives you, you can simply use Newton's law of universal gravitation. You need to adjust it to Earth masses and the result to Earth gravity, so it would look like this:
(G * (m * m_E) / ((1000 * r)^2))/g
Where G is the gravitational constant (6.674E-11 m^3/(kg*s^2) ), m is the target planet's mass, m_E is Earth's mass (5.972E+24 kg), r is the target planet's radius in km (hence the multiplication by 1000 to get meters) and g is Earth's gravity (9.81 m/s^2, or can be calculated as (G*m_E)/(r_E^2) ). That last division is so that you get your result in Earth g-s.
If you calculate this for your planet, you'll see that the result that Elite gives you is correct. But if you're looking at the surface levels of the two planets, you're comparing the gravitational pull at two different distances.