Because...physics....?
Yeah I think stars need to produce more heat based on their class and luminosity aswell
^^This.
You are a lot closer to the Brown dwarf than the O class. If you go to the same distance you will find that there is no % with the Brown dwarf
I'm talking with a brown dwarf taking up half the screen vs a blue giant taking up half the screen. Try it.
This, you standard O class is a lot bigger then your standard brown dwarf, its easy to missjudge distance.
Make both angular diameters the same and try it!
Insert Father Ted "small, far away" clip here.
Edit: One thing to bear in mind is your actual distance from a star is directly related to it's radius which means they all appear to be the same size when you jump in.
Exactly, I'm glad someone on this thread agrees with me. The radiation you receive from two stars with identical surface temperature is proportional the surface area of the star (a Radius squared function) and inversely proportional to the square of the distance you are from the
star...
Simplifying the geometry (I know, I know) :
1) You have a star with apparent radius (Ra) and the radiation received from it (F)
2) Double your distance from the star it will look half as big (Ra/2) and radiation received will be quartered (F/4).
3) Double the RADIUS of the star but maintain surface temperature so that it looks just like it did in 1, i.e. Ra. and you have quadruple the surface area again, radiating 4 times as much back to radiation of (F).
Therefore, two stars of identical thermal colour (say 3000k) which look identical to the observer, (say Angular Radius 45 degrees) would bombard you with similar levels of radiation (heat).
In other words, hotter stars that look the same size as cooler ones would bombard you with significantly more radiation. "Black Body Radiation" has a T^4 relationship, meaning double the temperature increases radiation 16-fold!
700K and 20,000K are very different surface temperatures with a power 4 relationship means serious radiation.