UAs, Barnacles and other mysteries Thread 8 - The Canonn

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Th3 0utKa5t

Th3 0utKa5t
i have been debating with myself if this is going to be useful or not and decided it could be as valid as any other so here goes.

last night i had a thought abut the image the probe gives out.

Bottom left of the image: fly towards M5C from between the 2 sister planets M5a and M5b, i centered M5C directly between them.
Top Right of the image: drop probe just before you get to the atmos and honk it.
top left of the image: once honked the probe will do its EMP and a cloaking field of some sort from a beacon will drop.
bottom right of the image: beacon will give either a destination in the navcom or a landing vector for M5C

if a landing vector we could find an entrance to a cavern we can drive in to with the SRV.

now i know its a little basic but im no scientist so basic is all your getting from me lol, now the odd thing is when i did the above myself last night (without the UP) i was just entering the atmosphere when a big POI marker popped up on my HUD, worth investigating? you decide. *EDITED* i had just dropped un to orbital and was in the atmos but still worth a look?

In the meantime i will be searching for a UP to do said test again with a UP in tow, if anyone does this test i would be very interested in the result even if its nothing.

here is the video i made of my flight.

[video=youtube_share;y5UnXaR1BL0]https://youtu.be/y5UnXaR1BL0[/video]
 
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porowozek

porowozek
Is that Federal SomethingShip? Pic from newsletter, can't recognize it.


w590_628791_unknownprobedecoded.jpg
 

Kerrec Snowmane

K
LordZoltan said:
What if the image didn't represent a circle, but a sphere/hemisphere, with the viewpoint slightly from above the plane made by the equator?
Click to expand...

I had to science this.

First, proof that my method DOES produce equal angles given a 3D model that is split with equal angles:

oXezX0p.png


And now, the same sphere (half actually) seem 2 degrees above the plane of the equator:

Abd4uPq.png


So, the first 2 measurements from the incorrect equator plane equally distribute the error. One measurement is 8 deg, the other is 12 deg. All other angles show the correct 10 deg.
 

Kerrec Snowmane

K
karantza said:
It just means that Log_x (y) = Log_a (y) / Log_a(x), where 'a' can be anything. Specifically in this case, it means that no matter what base you chose for your logarithm in the spectrogram, it will only change the vertical stretching of the image, it won't distort it in any other way. And the vertical stretching is already arbitrary, so, the base is irrelevant.
Click to expand...

I don't pretend to understand what the spectograph programs do. I was under the impression that the time axis (X) is not scaled at all. The frequency axis (Y) is scaled log 10 (for most of the images we have referenced) and then stretched or shrunk on the Y axis to produce a circle.

I am pretty sure I'm right, because the time axis produces acceptable symmetry with the grid pattern.
 

knowles2

K
Federation must be deploying nearly every capital ship it has to defend the Barnacle sites. I know the Feds want to protect alien life but this seem to me going a bit to far. Especially their been no word about it publically, we were getting at weekly news bulletins when they were busy wiping out those onions.
 
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dumbo

D
Colonel Kenney said:
There is a way to encrypt morse I posted links and some decoders.

It does make sense that some form of encryption would be done by any computer based system or intelligence but I thought these were primitive lifeforms. Also why would some stuff be in the clear in a human made code?
Click to expand...

Morse code is a set of dots/dashes, of variable length. (v is 4 bits, e is 1).

Listening to a portion of the UP audio, it instead seems to consist of 'blocks' of 3 bits.

|-- ||- |-- ||- -|- etc.

Which seems similar to the binary on the outside of the image, rather than morse code.
 

LordZoltan

LordZoltan
Kerrec Snowmane said:
I had to science this.

First, proof that my method DOES produce equal angles given a 3D model that is split with equal angles:

http://i.imgur.com/oXezX0p.png

And now, the same sphere (half actually) seem 2 degrees above the plane of the equator:

http://i.imgur.com/Abd4uPq.png

So, the first 2 measurements from the incorrect equator plane equally distribute the error. One measurement is 8 deg, the other is 12 deg. All other angles show the correct 10 deg.
Click to expand...

Try doing it in perspective. I think.

Big respect for the work either way, though - +rep!
 

MadDogMurdock

MadDogMurdock
Quick questions on the scaling thing.

Do the audio tools let you pick a scale or is it either linear or logarithmic (10)?
I think that the central image is meant to be an exact circle, so is it an exact circle at log (10) or not?
 

LordZoltan

LordZoltan
Kerrec Snowmane said:
I don't pretend to understand what the spectograph programs do. I was under the impression that the time axis (X) is not scaled at all. The frequency axis (Y) is scaled log 10 (for most of the images we have referenced) and then stretched or shrunk on the Y axis to produce a circle.

I am pretty sure I'm right, because the time axis produces acceptable symmetry with the grid pattern.
Click to expand...

y axis is plotted log(n) which isn't the same as log 10
 

LordZoltan

LordZoltan
CMDR Ash said:
Who is taking part in the educating Ed for the Canonn? I would like to put my name forward! *steps forward politely*
Click to expand...

not decided yet, although a couple of names are already on the board.

there could be a way for more people to get involved - announcements will be made once discussions have been had! :)
 

Kerrec Snowmane

K
MadDogMurdock said:
Quick questions on the scaling thing.

Do the audio tools let you pick a scale or is it either linear or logarithmic (10)?
I think that the central image is meant to be an exact circle, so is it an exact circle at log (10) or not?
Click to expand...

I'm not an expert. I downloaded Audacity only last nght and managed to generate the spectrograph. But you can drag the window to stretch the image in the vertical axis after it's been scaled by the software. I couldn't find an "unstretched" setting. So getting it to be circular is "easy", but if that is the correct way to do it, is questionable.
 

CMDRDemonEyesCain

C
Well guys, ive come to the conclusion that theres a wreckage/strandage on the dark side of M5C. Im 8500LY/8 straight hours of flight out on my way back from a multi month exploration expedition/Jaques and plan on stopping by Gateway to drop off my data, then Im going to go look for the wreckage. If i start after work i should be there around 2-3am central time. Im Demon Eyes Cain on XBL if any CMDRs would like to join me. Wish me luck, ill post here and on reddit if i find anything. I feel like ive got a good shot because im unusually lucky when it comes to stuff.
 

LordZoltan

LordZoltan
MadDogMurdock said:
But what is the value of n?
Click to expand...

the input frequency.

e.g. peaks at 500hz, 5khz and 15000khz are plotted at log(500), log(5000), log(15000) then scaled to the output height of the bitmap into which the spectrogram is drawn

edit too: i think it is base 10, too, sorry. log(x) in engineering is log 10 normally.
 
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Frambitam

F
MadDogMurdock said:
Quick questions on the scaling thing.

Do the audio tools let you pick a scale or is it either linear or logarithmic (10)?
I think that the central image is meant to be an exact circle, so is it an exact circle at log (10) or not?
Click to expand...

Something I wondered about too, most likely we have the correct scaling since we get a nice circle... but log(10) does feel kind of... well... we're back to the base 10 argument. Is it possible to check using ln instead?
 
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