Why referring to newtonian stuff for an ED ingame question? -Those two just doesn't fit together
Type-6 as fast as an Eagle.... Come on....
- Thread starter kiario
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Why referring to newtonian stuff for an ED ingame question? -Those two just doesn't fit together
Sorry that is wrong... you can only go as fast as the thrust coming from the rocket even with endless fuel it would still get to a certain speed and not be able to go beyond that speed.
And yes the lighter ship would never be caught, there would eventually be a gap that would not change between the 2 flying in a straight line.
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No, that's wrong, thrust only affects acceleration, the actual speed limit is c. Think about it: speed does not change how much force the thruster puts on the ship. And if we assume limitless fuel, mass does not change either. And since acceleration = force per mass, it remains constant. Only when speed gets close to c does relativity step in and increase mass and therefore decrease acceleration.
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OP is comparing apples and pears unfortunately. Like someone mentioned before turboprop vs jet engine.
Size is irrelevant here. There are bigger planes that go as fast or faster than the f/a-18, eg the sr-71 blackbird or the xb-70 valkyrie. Vmax in aircraft is only dependent on the engines and how the aircraft is built shapewise. Strap a jet engine to a Cessna its structure won't withstand high pressure from fast flight and just breaks apart.
Rockets going to space have far greater mass yet they go much faster as in as fast as necessary to escape thecearths gravitational pull. Size, mass or shape don't influence vmax in space.
Hope this helps.
Size is irrelevant here. There are bigger planes that go as fast or faster than the f/a-18, eg the sr-71 blackbird or the xb-70 valkyrie. Vmax in aircraft is only dependent on the engines and how the aircraft is built shapewise. Strap a jet engine to a Cessna its structure won't withstand high pressure from fast flight and just breaks apart.
Rockets going to space have far greater mass yet they go much faster as in as fast as necessary to escape thecearths gravitational pull. Size, mass or shape don't influence vmax in space.
Hope this helps.
Um, what?
Well I will agree to disagree but I think you will find thrust is not an infinite thing.
i,e, the speed at which the thrust is coming out pushing the ships will eventually be equalled by the ship forward speed at that point you cannot go any faster then the thrust from the engine!
Forget about the ED universe; there is A LOT of wrong physics in this thread!
To say nothing of the fact that everybody is ignoring the entire concept of relative speed.
To say nothing of the fact that everybody is ignoring the entire concept of relative speed.
No, no, you are somehow thinking that the thrust is relative to space, when it is actually relative to the ship (the thruster is attached to the ship
), and therefore does not change however fast the ship goes!Sorry, no. You are imagining some counter force like friction pushing back.
Only force changes speed.
And why would you think any of this?
Certainly explains how people drive around my way. When I moved to the US I discovered that "speed limit" means "if you go any slower than this we'll ram you off the road".
I realize that this isn't particularly helpful to this thread, but since the real answer is "they made a game design decision", I don't know what else can be said.
I agree, I'd also go further and say some of the bigger ships manoeuver too fast as well.
Sound like somebody in a hairdressers car got burnt off the lights by White Van Man.
If it's any consolation, my T9 does 130 with 4 pips to ENG...
+1 so funny
No, no, you are somehow thinking that the thrust is relative to space, when it is actually relative to the ship (the thruster is attached to the ship
?!? anyway good convo, now off to do some Eagle hunting in my "nitroed type 6" vrooooom
+1 so funny
?!? anyway good convo, now off to do some Eagle hunting in my "nitroed type 6" vrooooom
Aye, quick, it looks like it might be getting educational around here. Can't run the risk of learning stuff
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By "at these speeds" I assume you're not meaning 400m/s approx? In ED the ships never travel fast enough for spaceship geometry to become relevant - you'd actually have to be travelling at 99.significant something% for it to become relevent.
Aye, quick, it looks like it might be getting educational around here. Can't run the risk of learning stuff
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By "at these speeds" I assume you're not meaning 400m/s approx? In ED the ships never travel fast enough for spaceship geometry to become relevant - you'd actually have to be travelling at 99.significant something% for it to become relevent.
Educational enough for you lol http://en.wikipedia.org/wiki/Thrust
Please note:
A rocket is propelled forward by a thrust force equal in magnitude, but opposite in direction, to the time-rate of momentum change of the exhaust gas accelerated from the combustion chamber through the rocket engine nozzle. This is the exhaust velocity with respect to the rocket, times the time-rate at which the mass is expelled, or in mathematical terms:
Educational enough for you lol http://en.wikipedia.org/wiki/Thrust
Please note:
A rocket is propelled forward by a thrust force equal in magnitude, but opposite in direction, to the time-rate of momentum change of the exhaust gas accelerated from the combustion chamber through the rocket engine nozzle. This is the exhaust velocity with respect to the rocket, times the time-rate at which the mass is expelled, or in mathematical terms:
where T is the thrust generated (force),is the rate of change of mass with respect to time (mass flow rate of exhaust), and v is the speed of the exhaust gases measured relative to the rocket.
Nothing wrong with your copy and paste abilities I see. Now, can you tell me what it means?
yes sorry about the paste lol but clear on wiki,
Basicaly all I am trying to say is you can not go faster then the "speed of the exhaust gases are leaving the engine", no matter the size of engine. as is said in wiki: "A rocket is propelled forward by a thrust force equal in magnitude, but opposite in direction "