@Jaiotu
There were several GalNet articles related to Salomé that didn't get much attention and were quickly forgotten.
Even more so for some of the other news that weren't blatantly, absolutely obvious related to the mysterious stuffs ingame.
Edit: And I just realized that one of the GalNet Articles I thought of has your name at the bottom ^^
Edit#2:
I remembered that one specifically because it mentions the connection of Rift, Conflux, Hawkins Gap and the Pleiades.
https://community.elitedangerous.com/en/galnet/uid/57badafa9657ba3925e88545
Again, extending the Fibonacci series in a different way, starting with Fi(0) we getIf we extend the following Fiboacci series:
.
665,1319,1984,3303
.
And extend these to get ten in number:
.
11,654,665,1319,1984,3303,5287,8590,13877,22467
.
If we then apply the SUM(10,7,5,3), we get the following:
For 10 we obtain 22467
For 7 we obtain 5287
For 5 we obtain 1984
For 3 we obtain 665
Do the various names in the list correspond to specific Galnet articles? At one point Drew said that the Rift would play out via Galnet. I think he also said, in a interview, that there is stuff in Galnet that we've missed.
Again, extending the Fibonacci series in a different way, starting with Fi(0) we get
.
0,1,1,2,3,5,6,11,654,665,1319 From this series we have F(0),F(1),F(2),F(3),F(4),F(5),F(6),F(7),F(8),F(9),F(10).
.
Again not sure if to apply SUM(10,7,5,3), so that:
10 = F(10) = 1319
7 = F(7) = 11
5 = F(5) = 5
3 = F(3) = 2
SUM Total 1337
Again, extending the Fibonacci series in a different way, starting with Fi(0) we get
.
0,1,1,2,3,5,6,11,654,665,1319 From this series we have F(0),F(1),F(2),F(3),F(4),F(5),F(6),F(7),F(8),F(9),F(10).
.
Again not sure if to apply SUM(10,7,5,3), so that:
10 = F(10) = 1319
7 = F(7) = 11
5 = F(5) = 5
3 = F(3) = 2
SUM Total 1337
This is absolutely mindblowing, and yes: Elite! Good work, CMDR!
So, stand back for a hip shot attempt.
DB-IB 1984 Elite. Fi(0) = where it all started. Lave.
Yes.
[noob]
Again, extending the Fibonacci series in a different way, starting with Fi(0) we get
.
0,1,1,2,3,5,6,11,654,665,1319 From this series we have F(0),F(1),F(2),F(3),F(4),F(5),F(6),F(7),F(8),F(9),F(10).
.
Again not sure if to apply SUM(10,7,5,3), so that:
10 = F(10) = 1319
7 = F(7) = 11
5 = F(5) = 5
3 = F(3) = 2
SUM Total 1337
If you were using 1319, 1984, 3303 as points in a Fibonacci-esque series, then I would have thought it would look like this:Again, extending the Fibonacci series in a different way, starting with Fi(0) we get
.
0,1,1,2,3,5,6,11,654,665,1319 From this series we have F(0),F(1),F(2),F(3),F(4),F(5),F(6),F(7),F(8),F(9),F(10).
.
Again not sure if to apply SUM(10,7,5,3), so that:
10 = F(10) = 1319
7 = F(7) = 11
5 = F(5) = 5
3 = F(3) = 2
SUM Total 1337
0,1,1,2,3,5,6,11,654,665,1319 From this series we have F(0),F(1),F(2),F(3),F(4),F(5),F(6),F(7),F(8),F(9),F(10).
...
SUM Total 1337
Thus there are two locations you need to identify. Alacrity is indicated.
A hint. Both the video and the GalNet article resolve to a single location apiece. Good hunting, CMDRs.