I'm in - made it back to Colonia and rumbling about there now afraid of all the ships. It's a Saturday so I am off work which is a bonus. How can I not miss this?
Exploration - When worlds colide
- Thread starter Ben Ryder
- Start date
I'm quite close to Kyloasly by coincidence (heading from Colonia to SagA using "free" navigation). I believe I'll not miss such unique opportunity .. thank you for tip [up]I landed on 2C last night and 2B was .2ls away. 8 hours later it was .18ls out, so if that pace contines, looks like it will hit around 13:00 Saturday (GMT) or 08:00 EST.
Just a heads up: the relative speed fluctuates, so you may be off in your prediction.
The angular speed of the moon's orbit varies depending on the eccentricity and where it is in it's orbit at the time.
As we found out last time, approach speed is not constant because the eccentricities of the two moons are not aligned so they move at different speeds relative to each other.
You can see my calculations for the last collision earlier in this thread. I had to average the speed over a full orbit or around 36 hours I think.
https://forums.frontier.co.uk/showt...orlds-colide?p=6026525&viewfull=1#post6026525
The average speed should be the same now as it was before so you may be able to use some of the numbers from my previous calculations to get a more accurate estimate of the collision time.
Videos posted in this thread from the previous collision can give you exact timing of the last collision.
From a linear distance of 0.1ls, I got an average approach speed over 67 hours of ~0.001391 Ls/hr or ~0.416983 Mm/hr
Also remember the distance shown on your hud is from your ship to the center of the other moon, not the surface.
So to get the surface to surface distance, you need to subtract the moon's radius.
I can't be there this time so I'm looking forward to your accounts of the collision this time around.
Remember to have the moon you are landing on selected to avoid the frame of reference problems some commanders had last time.
When the moons are close, your ship can end up locked to the relative motion of the wrong moon causing your ship to move at around 115m/s relative to the ground, even if your ship is stopped.
This caused a couple of ship rebuys the last time. It almost got me but I was able to boost up and back into SC.
As we found out last time, approach speed is not constant because the eccentricities of the two moons are not aligned so they move at different speeds relative to each other.
You can see my calculations for the last collision earlier in this thread. I had to average the speed over a full orbit or around 36 hours I think.
https://forums.frontier.co.uk/showt...orlds-colide?p=6026525&viewfull=1#post6026525
The average speed should be the same now as it was before so you may be able to use some of the numbers from my previous calculations to get a more accurate estimate of the collision time.
Videos posted in this thread from the previous collision can give you exact timing of the last collision.
From a linear distance of 0.1ls, I got an average approach speed over 67 hours of ~0.001391 Ls/hr or ~0.416983 Mm/hr
Also remember the distance shown on your hud is from your ship to the center of the other moon, not the surface.
So to get the surface to surface distance, you need to subtract the moon's radius.
I can't be there this time so I'm looking forward to your accounts of the collision this time around.
Remember to have the moon you are landing on selected to avoid the frame of reference problems some commanders had last time.
When the moons are close, your ship can end up locked to the relative motion of the wrong moon causing your ship to move at around 115m/s relative to the ground, even if your ship is stopped.
This caused a couple of ship rebuys the last time. It almost got me but I was able to boost up and back into SC.
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*singing*
Science Fiction, Double Feature...
(I wish I had realised how dangerous this might prove earlier - I would have called in a faster ship.)
Science Fiction, Double Feature...
(I wish I had realised how dangerous this might prove earlier - I would have called in a faster ship.)
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This ain't like dusting crops lady...
I feel the same about TV and radio :BDamn you, physics!
Always scheduling cool stuff when I'm not around!
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i have just landed on 2c
If anyone is on site now, post a distance reading from the surface of one of the moons, with a precise time stamp (in game time) and what moon you're on, and I'll see if I can narrow down the collision time window.
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My prediction is for 13:06 on Sunday the 25th (based on 132.9 days after the previous occurrence) but I may very well be missing something! They were 0.14ls about an hour ago, I'll post an update later today when I log back in.
At the moment, I'd give that a + or - 12 hour window. In the absence of more accurate readings, Saturday is just based on the 133 day estimate of the time between collisions.
Based on the average linear approach speed I had last time of ~0.001391 Ls/hr or ~0.416983 Mm/hr, that would put the collision around 100.63 hours or 4.19 days from an hour ago. That would make it Sunday, give or take a few hours due to the inconsistent relative speed and I didn't subtract the moon's radius since I didn't know which moon you measured from.
Since all of the numbers shown in the game client are rounded off or truncated, it makes it nearly impossible to get numbers accurate enough predict the timing to within a 1 hour window.
We can get much more accurate when the distance display goes from Ls to Mm.
2C has a radius of 1,108 km. 2B has a radius of 1,347 km
Approach speed should be close to 416.983 Km/hr or ~115.8 m/s
So the moon's radius accounts for 2.65 - 3.23 hrs.
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i should be able to give you a distance and a timestamp of B from C as i am there now i will post the distance with a precise timestamp once i have it
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It would be more accurate if you were at the closest point between the two.
The math based on a distance reading is really predicting when the other moon will contact the surface where your ship is located when it took the reading.
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i should be able to give you a distance and a timestamp of B from C as i am there now i will post the distance with a precise timestamp
didnt mean to post twice
ok i will make sure i do