Robert Maynard
Volunteer Moderator
How about now: https://1drv.ms/x/s!AhwMM1shYJvNohBiIN_5yLFmqWzy
Charon Circumnavigation
- Thread starter Ian Phillips
- Start date
Ian Phillips
Volunteer Moderator
This link doesn't work for me any more, as it just tells me to go north instead of following the great circle around the planet.
Ian Phillips
Volunteer Moderator
Latitude Longitude Heading
69.00000° 39.00000° 90.00000°
Those figures agree with my workings out in that it gives
270.00° 0.00000° -51.00000° 21.00000°
So the ..... arrrrggghhhh..... My brain hurts
Edit:
I'm currently at (roughly) -74 south and -108 east.
Your sheet shows that I did indeed need to head north again because the great circle I am following reaches its own most southerly point at -69.3697
And on the bearing calculation link, the path I need to follow would be drawn as a sine wave with the top and bottom peaks touching 69.3697 and -69.3697 not as a line that disappears off the bottom of the map.....
Learning things!
So I've zagged south when I didn't need to, and am now way too far south (again).
To get to the 3/4 point on my great circle, my heading is roughly 60 degrees from my current position. (I hope
)
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Robert Maynard
Volunteer Moderator
You cannot circumnavigate a planet at 90°/ 270° unless at the equator.
What was your original heading, right at the beginning?
Ian Phillips
Volunteer Moderator
No idea! - I went west to find the start of a huge canyon, then later I got a heading of about 155 degrees, but that was from a position well to the south and west of my starting point
edit:
The Bearing link gives a 90 bearing if I enter my start and antipodal points.
Edit 2
i think I'll settle for an initial 135 bearing which would give a 3/4 waypoint of
270.00° 14.67906° -94.03263°
and that is a bearing of 20 degrees, roughly.
good enough, as it is roughly correct, if I draw a sine wave by eye across the map on the bearing link.
edit:
The Bearing link gives a 90 bearing if I enter my start and antipodal points.
Edit 2
i think I'll settle for an initial 135 bearing which would give a 3/4 waypoint of
270.00° 14.67906° -94.03263°
and that is a bearing of 20 degrees, roughly.
good enough, as it is roughly correct, if I draw a sine wave by eye across the map on the bearing link.
Last edited:
Ian Phillips
Volunteer Moderator
On a positive note, I saw Pluto again today
Take what you can get. Of course, you could always re-start doing the equatorial route!! [wacky]On a positive note, I saw Pluto again today
Ian Phillips
Volunteer Moderator
So, I woke up early this morning with the answer.
It's already in the thread - A challenge: Who can find it?
It's already in the thread - A challenge: Who can find it?
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Robert Maynard
Volunteer Moderator
Ian Phillips
Volunteer Moderator
Nope
Robert Maynard
Volunteer Moderator
Pah!Nope
Ian Phillips
Volunteer Moderator
Want a clue?
Robert Maynard
Volunteer Moderator
Oh, go on then....
Ian Phillips
Volunteer Moderator
What do you need to be able to define a great circle?
A sphere
OH! So much THIS!How about a sextant.
Ian Phillips
Volunteer Moderator
Technically, yes a sphere
But that's not the answer.
But that's not the answer.
Two points on said sphere.Technically, yes a sphere
But that's not the answer.
Ian Phillips
Volunteer Moderator
Almost. What if those two points are (for example) the poles?