Too dark to see the moon in the sky at the moment but the hud says the B moon is now now ~0.49ls away.
How many are planning to be here on the day?
In Open or FleetComm?
How many are planning to be here on the day?
In Open or FleetComm?
Exploration - When worlds colide
- Thread starter Ben Ryder
- Start date
Heading out there right now! ~4000Ly down, ~19000Ly to go... maybe with some sightseeing on the way. I've always wanted to visit Colonia.
I'll be in FleetComm.
I'll be in FleetComm.
21k Ly out, coming in from Beagle Point direction. I'm going to stop by the Segnao Starburst for some surveying, and then head down here, hopefully with a day to spare.
Has anyone figured out a landing site for this?
Has anyone figured out a landing site for this?
World's Collide always makes me think of this song: https://www.youtube.com/watch?v=lsV500W4BHU
(I love Powerman 5000).
(I love Powerman 5000).
I'm on the C moon, landed near the equator on the side facing the planet.
The B moon should pass the c moon on the inside, eclipsing the planet, so as long as you have the planet above you, the view should be good. Though maybe it would be better a bit north or south so you don't get clipped inside the moon as it passes through.
They're both tidally locked so you won't rotate out of view. On the equator at about -30 degrees (~0.0 x -30.0) the planet is directly above at 90 degrees straight up. The B moon is due east at 17 degrees elevation.
At this spot, if it's possible to get crushed, you probably will. Or you'll clip through the moon and look at a wire frame of the inside of it.
Photos taken today.
Any suggestions for how far away would be a good vantage point? I'm sure you'll get better views from orbit, on the trailing side so neither moon is coming right at you. Trouble is you can't control which frame of reference you'll be in. In theory the game should put you in the reference frame of the planet you are closest to. Since things are moving, that can change quickly and you may find yourself moving very fast with respect to one moon or the other.
It would be amazing if you could be in the air and get swept up by the B moon, switching planets as it passes.
Judging from Ben rider's photos in the original post, the area of overlap when the moons clip through each other seems to be about 30 degrees. So 30 degrees north or south should keep you from being squeezed in between the two.
Update: I didn't find any geysers. Unless anyone has a better idea, I think the -30 meridian is the best location. I'm parked 30 degrees north at ~ 30.00 by -30.00. At this location, the B moon is roughly due east and the gas giant is due south at ~60 degrees elevation. And, you can see them both at the same time.
You could of course park on the B moon but I thought it would be easier to position here on C. Finding the right meridian on B will take a bit more work and you won't have the gas giant in the background.
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I plan to record and put it on my YouTube.
But I can only get one angle on it. Hopefully some others will record also.
But I can only get one angle on it. Hopefully some others will record also.
Ohhh, I wish I could be there but I'll be departing out in the 14th so I'll have to watch you
how far from sol is this?
also I wonder if an SRV could transfer from one planet to the next, this would be a first
how far from sol is this?
also I wonder if an SRV could transfer from one planet to the next, this would be a first
I'd think you can. Somebody once send an SRV to a station.
Wait what? *opens youtube and starts NSA level research*
It's about ~1400ly west of Colonia. https://www.edsm.net/en/system/id/13944236/name/Kyloasly+DA-A+f69
Distance to Sol: 23,334.89 ly
Distance to Colonia: 1,408.59 ly
In theory it might be possible to jump planets with an SRV but the positioning and timing would have to be perfect.
Gravity is light so your SRV can jump high. If you are right on the edge of the circular contact area at the peak of the collision, you might be able to jump up and fall down on the other moon.
The trouble will be predicting exactly where the edges of the contact area will be.
There are some photos in the original post that show the previous collision. If you are inside that contact area you should be able to see the contact edge approaching and jump just before it reaches you or just after it passes you. You might just clip through the other moon and get the inside wire frame view until it passes.
From what I've seen in videos of other glitches, the game puts you in the frame of reference of where you drop out of supercruise. After that, celestial bodies that collide are visual ghosts.
BUT .. When I traveled between planets using only thrusters, there was a transition at the gravitational halfway point where I started falling toward the destination planet and no longer needed to use thrusters.
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This was also given a GMP POI: Sword of Damocles
A short 12 hour timelapse:
[video=youtube;-rLCtvD7Pqk]https://youtu.be/-rLCtvD7Pqk[/video]
[video=youtube;-rLCtvD7Pqk]https://youtu.be/-rLCtvD7Pqk[/video]
0.39ls away now.
https://i.imgur.com/lx2Yawx.png
https://i.imgur.com/MtV7cua.png
Does anyone know how long the collision will last? Malenfant's calculations, as good as they are, are only predicting the day, not the time. "Around October 14th" is a lot of hours to sit and watch and wait.
It might be easy to miss if you aren't logged on at just the right time. Fortunately, it's a Saturday so I can log in Friday night and keep checking frequently until it's obviously close.
https://i.imgur.com/lx2Yawx.png
https://i.imgur.com/MtV7cua.png
Does anyone know how long the collision will last? Malenfant's calculations, as good as they are, are only predicting the day, not the time. "Around October 14th" is a lot of hours to sit and watch and wait.
It might be easy to miss if you aren't logged on at just the right time. Fortunately, it's a Saturday so I can log in Friday night and keep checking frequently until it's obviously close.
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OK, More Math....
I'm trying to tighten up the prediction for the actual collision time.
Malenfant's math predicted the next collision down to the day but not the time.
I wanted to attempt to get the approximate time of the collision, so here goes.
I've been checking the distance to the B moon from the surface of the C moon every few days.
The distance displayed to the moon is not the actual distance to the surface, It's the distance to the center of the moon.
The radius of the B moon is 1,347 km or 0.004493108Ls. The C moon where I'm parked reads 1.11Mm away which is consistent with the moons radius of 1,108 km, but as you can see there's some rounding going on. Since the distance is rounded to two decimal places, I'll use 0.01Ls as the start of the event.
Since the approach is moving on a curve, I don't expect the aproach speed to be linear. I think at this point in the orbit, the approach speed should accelerate as the curve becomes more linear.
I don't know the math to take the curvature into account and I don't have an accurate way to measure the angles. Since the two are so close now, I'm hoping the curve will only have a negligible effect at this point.
On Sept 21 at ~03:48 game time the B moon was at 0.79Ls
Today, Oct 5 at ~02:30 game time the B moon is at 0.35Ls
That's ~14 days or more accurately 334 hours and a difference of 0.44Ls
If my math is right, that's ~0.03143Ls per day, or more accurately 0.001317Ls per hour
That's 258.09 hours until the B moon is 0.01Ls away, or 10.75 days from now, or October 15th.
258.09 hours past ~2:30am October 5th would be October 15th at 20:35 GMT.
Actually, almost certainly, sometime before that since the approach speed isn't linear and the measurements are all rounded to two decimal places.
So I don't actually know exactly when it will happen, I just know it will probably be before that time.
I will of course try to update these calculations as they get closer.
At 0.001317Ls per hour, I think the moons will be within 1 radius of each other for about 3.4 hours.
If someone watching this thread has some better maths than I do, maybe they can improve on these calculations.
P.S. I make the angle between the two moons to be ~29 degrees right now. (03:46am on Oct 5)
I measured the angle from a screenshot using GIMP, eyeballing the center of the planet and the moons, so give or take a half a degree.
At ~3.78 degrees every ~1.4 days or 2.7 degrees per day or 0.1125 degrees per hour.
That's 257.7 hours until 0 degrees. (Oct 15th at 21:28)
That's close to my previous number. The positioning of my ship for the screenshot and the measurement of the angle aren't particularly accurate though.
Anyway, it increases my confidence that the collision will be in the evening on Oct 15th (GMT/Game Time)
I'm trying to tighten up the prediction for the actual collision time.
Malenfant's math predicted the next collision down to the day but not the time.
I wanted to attempt to get the approximate time of the collision, so here goes.
I've been checking the distance to the B moon from the surface of the C moon every few days.
The distance displayed to the moon is not the actual distance to the surface, It's the distance to the center of the moon.
The radius of the B moon is 1,347 km or 0.004493108Ls. The C moon where I'm parked reads 1.11Mm away which is consistent with the moons radius of 1,108 km, but as you can see there's some rounding going on. Since the distance is rounded to two decimal places, I'll use 0.01Ls as the start of the event.
Since the approach is moving on a curve, I don't expect the aproach speed to be linear. I think at this point in the orbit, the approach speed should accelerate as the curve becomes more linear.
I don't know the math to take the curvature into account and I don't have an accurate way to measure the angles. Since the two are so close now, I'm hoping the curve will only have a negligible effect at this point.
On Sept 21 at ~03:48 game time the B moon was at 0.79Ls
Today, Oct 5 at ~02:30 game time the B moon is at 0.35Ls
That's ~14 days or more accurately 334 hours and a difference of 0.44Ls
If my math is right, that's ~0.03143Ls per day, or more accurately 0.001317Ls per hour
That's 258.09 hours until the B moon is 0.01Ls away, or 10.75 days from now, or October 15th.
258.09 hours past ~2:30am October 5th would be October 15th at 20:35 GMT.
Actually, almost certainly, sometime before that since the approach speed isn't linear and the measurements are all rounded to two decimal places.
So I don't actually know exactly when it will happen, I just know it will probably be before that time.
I will of course try to update these calculations as they get closer.
At 0.001317Ls per hour, I think the moons will be within 1 radius of each other for about 3.4 hours.
If someone watching this thread has some better maths than I do, maybe they can improve on these calculations.
P.S. I make the angle between the two moons to be ~29 degrees right now. (03:46am on Oct 5)
I measured the angle from a screenshot using GIMP, eyeballing the center of the planet and the moons, so give or take a half a degree.
At ~3.78 degrees every ~1.4 days or 2.7 degrees per day or 0.1125 degrees per hour.
That's 257.7 hours until 0 degrees. (Oct 15th at 21:28)
That's close to my previous number. The positioning of my ship for the screenshot and the measurement of the angle aren't particularly accurate though.
Anyway, it increases my confidence that the collision will be in the evening on Oct 15th (GMT/Game Time)
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